MATH SOLVE

4 months ago

Q:
# A ramp with a constant incline is made to connect a driveway to a front door. At a point 4 feet from the driveway, the height of the ramp is 12 inches. At a point 6 feet from the driveway, the height of the ramp is 18 inches. What is the rate of change of the ramp’s incline?

Accepted Solution

A:

recall that, there are 12 inches in 1 foot, now, when the ramp is 4 feet away, that's 4*12 inches, and when it's 6 feet away, that's 6*12 inches.

[tex]\bf \begin{array}{ccll} \stackrel{\textit{inches from driveway}}{x}&\stackrel{\textit{inches of ramp's height}}{y}\\ \text{\textemdash\textemdash\textemdash}&\text{\textemdash\textemdash\textemdash}\\ 48&12\\ 72&18 \end{array}\\\\ -------------------------------[/tex]

[tex]\bf \begin{array}{lllll} &x_1&y_1&x_2&y_2\\ % (a,b) &({{ 48}}\quad ,&{{ 12}})\quad % (c,d) &({{ 72}}\quad ,&{{ 18}}) \end{array} \\\\\\ % slope = m \stackrel{\textit{average rate of change}}{slope = {{ m}}= \cfrac{rise}{run}} \implies \cfrac{{{ y_2}}-{{ y_1}}}{{{ x_2}}-{{ x_1}}}\implies \cfrac{18-12}{72-48}\implies \cfrac{6}{24}\implies \cfrac{1}{4}[/tex]

[tex]\bf \begin{array}{ccll} \stackrel{\textit{inches from driveway}}{x}&\stackrel{\textit{inches of ramp's height}}{y}\\ \text{\textemdash\textemdash\textemdash}&\text{\textemdash\textemdash\textemdash}\\ 48&12\\ 72&18 \end{array}\\\\ -------------------------------[/tex]

[tex]\bf \begin{array}{lllll} &x_1&y_1&x_2&y_2\\ % (a,b) &({{ 48}}\quad ,&{{ 12}})\quad % (c,d) &({{ 72}}\quad ,&{{ 18}}) \end{array} \\\\\\ % slope = m \stackrel{\textit{average rate of change}}{slope = {{ m}}= \cfrac{rise}{run}} \implies \cfrac{{{ y_2}}-{{ y_1}}}{{{ x_2}}-{{ x_1}}}\implies \cfrac{18-12}{72-48}\implies \cfrac{6}{24}\implies \cfrac{1}{4}[/tex]